(2x+20)^2+4x^2=2000

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Solution for (2x+20)^2+4x^2=2000 equation: 



(2x+20)^2+4x^2=2000

We move all terms to the left:

(2x+20)^2+4x^2-(2000)=0

We move all terms containing x to the left, all other terms to the right

4x^2+(2x+20)^2=2000

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